Q^2-16Q+28=0

Solution for Q^2-16Q+28=0 equation:

Simplifying
Q2 + -16Q + 28 = 0

Reorder the terms:
28 + -16Q + Q2 = 0

Solving
28 + -16Q + Q2 = 0

Solving for variable 'Q'.

Factor a trinomial.
(2 + -1Q)(14 + -1Q) = 0

Subproblem 1
Set the factor '(2 + -1Q)' equal to zero and attempt to solve:

Simplifying
2 + -1Q = 0

Solving
2 + -1Q = 0

Move all terms containing Q to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1Q = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1Q = 0 + -2
-1Q = 0 + -2

Combine like terms: 0 + -2 = -2
-1Q = -2

Divide each side by '-1'.
Q = 2

Simplifying
Q = 2
Subproblem 2
Set the factor '(14 + -1Q)' equal to zero and attempt to solve:

Simplifying
14 + -1Q = 0

Solving
14 + -1Q = 0

Move all terms containing Q to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + -1Q = 0 + -14

Combine like terms: 14 + -14 = 0
0 + -1Q = 0 + -14
-1Q = 0 + -14

Combine like terms: 0 + -14 = -14
-1Q = -14

Divide each side by '-1'.
Q = 14

Simplifying
Q = 14
Solution
Q = {2, 14}